3.2342 \(\int \frac{(A+B x) \left (a+b x+c x^2\right )^3}{(d+e x)^5} \, dx\)

Optimal. Leaf size=533 \[ \frac{A e (2 c d-b e) \left (-2 c e (5 b d-3 a e)+b^2 e^2+10 c^2 d^2\right )-B \left (3 c e^2 \left (a^2 e^2-8 a b d e+10 b^2 d^2\right )-b^2 e^3 (4 b d-3 a e)-30 c^2 d^2 e (2 b d-a e)+35 c^3 d^4\right )}{e^8 (d+e x)}-\frac{c x \left (A c e (5 c d-3 b e)-3 B \left (-c e (5 b d-a e)+b^2 e^2+5 c^2 d^2\right )\right )}{e^7}+\frac{3 \left (a e^2-b d e+c d^2\right ) \left (B \left (-c d e (8 b d-3 a e)+b e^2 (2 b d-a e)+7 c^2 d^3\right )-A e \left (-c e (5 b d-a e)+b^2 e^2+5 c^2 d^2\right )\right )}{2 e^8 (d+e x)^2}-\frac{\log (d+e x) \left (B \left (-15 c^2 d e (3 b d-a e)+3 b c e^2 (5 b d-2 a e)-b^3 e^3+35 c^3 d^3\right )-3 A c e \left (-c e (5 b d-a e)+b^2 e^2+5 c^2 d^2\right )\right )}{e^8}+\frac{(B d-A e) \left (a e^2-b d e+c d^2\right )^3}{4 e^8 (d+e x)^4}+\frac{\left (a e^2-b d e+c d^2\right )^2 \left (3 A e (2 c d-b e)-B \left (7 c d^2-e (4 b d-a e)\right )\right )}{3 e^8 (d+e x)^3}-\frac{c^2 x^2 (-A c e-3 b B e+5 B c d)}{2 e^6}+\frac{B c^3 x^3}{3 e^5} \]

[Out]

-((c*(A*c*e*(5*c*d - 3*b*e) - 3*B*(5*c^2*d^2 + b^2*e^2 - c*e*(5*b*d - a*e)))*x)/
e^7) - (c^2*(5*B*c*d - 3*b*B*e - A*c*e)*x^2)/(2*e^6) + (B*c^3*x^3)/(3*e^5) + ((B
*d - A*e)*(c*d^2 - b*d*e + a*e^2)^3)/(4*e^8*(d + e*x)^4) + ((c*d^2 - b*d*e + a*e
^2)^2*(3*A*e*(2*c*d - b*e) - B*(7*c*d^2 - e*(4*b*d - a*e))))/(3*e^8*(d + e*x)^3)
+ (3*(c*d^2 - b*d*e + a*e^2)*(B*(7*c^2*d^3 - c*d*e*(8*b*d - 3*a*e) + b*e^2*(2*b
*d - a*e)) - A*e*(5*c^2*d^2 + b^2*e^2 - c*e*(5*b*d - a*e))))/(2*e^8*(d + e*x)^2)
+ (A*e*(2*c*d - b*e)*(10*c^2*d^2 + b^2*e^2 - 2*c*e*(5*b*d - 3*a*e)) - B*(35*c^3
*d^4 - b^2*e^3*(4*b*d - 3*a*e) - 30*c^2*d^2*e*(2*b*d - a*e) + 3*c*e^2*(10*b^2*d^
2 - 8*a*b*d*e + a^2*e^2)))/(e^8*(d + e*x)) - ((B*(35*c^3*d^3 - b^3*e^3 + 3*b*c*e
^2*(5*b*d - 2*a*e) - 15*c^2*d*e*(3*b*d - a*e)) - 3*A*c*e*(5*c^2*d^2 + b^2*e^2 -
c*e*(5*b*d - a*e)))*Log[d + e*x])/e^8

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Rubi [A]  time = 3.71996, antiderivative size = 531, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 1, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.04 \[ \frac{A e (2 c d-b e) \left (-2 c e (5 b d-3 a e)+b^2 e^2+10 c^2 d^2\right )-B \left (3 c e^2 \left (a^2 e^2-8 a b d e+10 b^2 d^2\right )-b^2 e^3 (4 b d-3 a e)-30 c^2 d^2 e (2 b d-a e)+35 c^3 d^4\right )}{e^8 (d+e x)}-\frac{c x \left (A c e (5 c d-3 b e)-3 B \left (-c e (5 b d-a e)+b^2 e^2+5 c^2 d^2\right )\right )}{e^7}+\frac{3 \left (a e^2-b d e+c d^2\right ) \left (B \left (-c d e (8 b d-3 a e)+b e^2 (2 b d-a e)+7 c^2 d^3\right )-A e \left (-c e (5 b d-a e)+b^2 e^2+5 c^2 d^2\right )\right )}{2 e^8 (d+e x)^2}-\frac{\log (d+e x) \left (B \left (-15 c^2 d e (3 b d-a e)+3 b c e^2 (5 b d-2 a e)-b^3 e^3+35 c^3 d^3\right )-3 A c e \left (-c e (5 b d-a e)+b^2 e^2+5 c^2 d^2\right )\right )}{e^8}+\frac{(B d-A e) \left (a e^2-b d e+c d^2\right )^3}{4 e^8 (d+e x)^4}-\frac{\left (a e^2-b d e+c d^2\right )^2 \left (-B e (4 b d-a e)-3 A e (2 c d-b e)+7 B c d^2\right )}{3 e^8 (d+e x)^3}-\frac{c^2 x^2 (-A c e-3 b B e+5 B c d)}{2 e^6}+\frac{B c^3 x^3}{3 e^5} \]

Antiderivative was successfully verified.

[In]  Int[((A + B*x)*(a + b*x + c*x^2)^3)/(d + e*x)^5,x]

[Out]

-((c*(A*c*e*(5*c*d - 3*b*e) - 3*B*(5*c^2*d^2 + b^2*e^2 - c*e*(5*b*d - a*e)))*x)/
e^7) - (c^2*(5*B*c*d - 3*b*B*e - A*c*e)*x^2)/(2*e^6) + (B*c^3*x^3)/(3*e^5) + ((B
*d - A*e)*(c*d^2 - b*d*e + a*e^2)^3)/(4*e^8*(d + e*x)^4) - ((c*d^2 - b*d*e + a*e
^2)^2*(7*B*c*d^2 - B*e*(4*b*d - a*e) - 3*A*e*(2*c*d - b*e)))/(3*e^8*(d + e*x)^3)
+ (3*(c*d^2 - b*d*e + a*e^2)*(B*(7*c^2*d^3 - c*d*e*(8*b*d - 3*a*e) + b*e^2*(2*b
*d - a*e)) - A*e*(5*c^2*d^2 + b^2*e^2 - c*e*(5*b*d - a*e))))/(2*e^8*(d + e*x)^2)
+ (A*e*(2*c*d - b*e)*(10*c^2*d^2 + b^2*e^2 - 2*c*e*(5*b*d - 3*a*e)) - B*(35*c^3
*d^4 - b^2*e^3*(4*b*d - 3*a*e) - 30*c^2*d^2*e*(2*b*d - a*e) + 3*c*e^2*(10*b^2*d^
2 - 8*a*b*d*e + a^2*e^2)))/(e^8*(d + e*x)) - ((B*(35*c^3*d^3 - b^3*e^3 + 3*b*c*e
^2*(5*b*d - 2*a*e) - 15*c^2*d*e*(3*b*d - a*e)) - 3*A*c*e*(5*c^2*d^2 + b^2*e^2 -
c*e*(5*b*d - a*e)))*Log[d + e*x])/e^8

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Rubi in Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  rubi_integrate((B*x+A)*(c*x**2+b*x+a)**3/(e*x+d)**5,x)

[Out]

Timed out

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Mathematica [A]  time = 0.951191, size = 496, normalized size = 0.93 \[ \frac{-\frac{12 \left (B \left (3 c e^2 \left (a^2 e^2-8 a b d e+10 b^2 d^2\right )+b^2 e^3 (3 a e-4 b d)+30 c^2 d^2 e (a e-2 b d)+35 c^3 d^4\right )+A e (b e-2 c d) \left (2 c e (3 a e-5 b d)+b^2 e^2+10 c^2 d^2\right )\right )}{d+e x}+12 c e x \left (3 B \left (c e (a e-5 b d)+b^2 e^2+5 c^2 d^2\right )+A c e (3 b e-5 c d)\right )+\frac{18 \left (e (a e-b d)+c d^2\right ) \left (B \left (c d e (3 a e-8 b d)+b e^2 (2 b d-a e)+7 c^2 d^3\right )-A e \left (c e (a e-5 b d)+b^2 e^2+5 c^2 d^2\right )\right )}{(d+e x)^2}+12 \log (d+e x) \left (3 A c e \left (c e (a e-5 b d)+b^2 e^2+5 c^2 d^2\right )+B \left (15 c^2 d e (3 b d-a e)+3 b c e^2 (2 a e-5 b d)+b^3 e^3-35 c^3 d^3\right )\right )+\frac{3 (B d-A e) \left (e (a e-b d)+c d^2\right )^3}{(d+e x)^4}-\frac{4 \left (e (a e-b d)+c d^2\right )^2 \left (B e (a e-4 b d)+3 A e (b e-2 c d)+7 B c d^2\right )}{(d+e x)^3}+6 c^2 e^2 x^2 (A c e+3 b B e-5 B c d)+4 B c^3 e^3 x^3}{12 e^8} \]

Antiderivative was successfully verified.

[In]  Integrate[((A + B*x)*(a + b*x + c*x^2)^3)/(d + e*x)^5,x]

[Out]

(12*c*e*(A*c*e*(-5*c*d + 3*b*e) + 3*B*(5*c^2*d^2 + b^2*e^2 + c*e*(-5*b*d + a*e))
)*x + 6*c^2*e^2*(-5*B*c*d + 3*b*B*e + A*c*e)*x^2 + 4*B*c^3*e^3*x^3 + (3*(B*d - A
*e)*(c*d^2 + e*(-(b*d) + a*e))^3)/(d + e*x)^4 - (4*(c*d^2 + e*(-(b*d) + a*e))^2*
(7*B*c*d^2 + B*e*(-4*b*d + a*e) + 3*A*e*(-2*c*d + b*e)))/(d + e*x)^3 + (18*(c*d^
2 + e*(-(b*d) + a*e))*(-(A*e*(5*c^2*d^2 + b^2*e^2 + c*e*(-5*b*d + a*e))) + B*(7*
c^2*d^3 + b*e^2*(2*b*d - a*e) + c*d*e*(-8*b*d + 3*a*e))))/(d + e*x)^2 - (12*(A*e
*(-2*c*d + b*e)*(10*c^2*d^2 + b^2*e^2 + 2*c*e*(-5*b*d + 3*a*e)) + B*(35*c^3*d^4
+ 30*c^2*d^2*e*(-2*b*d + a*e) + b^2*e^3*(-4*b*d + 3*a*e) + 3*c*e^2*(10*b^2*d^2 -
8*a*b*d*e + a^2*e^2))))/(d + e*x) + 12*(3*A*c*e*(5*c^2*d^2 + b^2*e^2 + c*e*(-5*
b*d + a*e)) + B*(-35*c^3*d^3 + b^3*e^3 + 15*c^2*d*e*(3*b*d - a*e) + 3*b*c*e^2*(-
5*b*d + 2*a*e)))*Log[d + e*x])/(12*e^8)

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Maple [B]  time = 0.027, size = 1605, normalized size = 3. \[ \text{result too large to display} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  int((B*x+A)*(c*x^2+b*x+a)^3/(e*x+d)^5,x)

[Out]

1/3*B*c^3*x^3/e^5-6/e^4/(e*x+d)^3*A*a*b*c*d^2+8/e^5/(e*x+d)^3*B*a*b*c*d^3+24/e^5
/(e*x+d)*B*a*b*c*d+3/2/e^4/(e*x+d)^4*A*d^3*a*b*c-3/2/e^5/(e*x+d)^4*B*d^4*a*b*c+9
/e^4/(e*x+d)^2*A*a*b*c*d-18/e^5/(e*x+d)^2*B*a*b*c*d^2+45/e^7*ln(e*x+d)*B*b*c^2*d
^2-6/e^4/(e*x+d)*A*a*b*c+4/e^5/(e*x+d)^3*A*b^2*c*d^3-5/e^6/(e*x+d)^3*A*b*c^2*d^4
+2/e^3/(e*x+d)^3*B*a^2*b*d-3/e^4/(e*x+d)^3*B*a^2*c*d^2-3/e^4/(e*x+d)^3*B*a*b^2*d
^2-5/e^6/(e*x+d)^3*B*a*c^2*d^4-5/e^6/(e*x+d)^3*B*b^2*c*d^4+6/e^7/(e*x+d)^3*B*b*c
^2*d^5-15*c^2/e^6*B*b*d*x+2/e^3/(e*x+d)^3*A*a^2*c*d+2/e^3/(e*x+d)^3*A*a*b^2*d+4/
e^5/(e*x+d)^3*A*a*c^2*d^3+3/4/e^6/(e*x+d)^4*B*a*c^2*d^5+3/4/e^6/(e*x+d)^4*B*b^2*
c*d^5-3/4/e^7/(e*x+d)^4*B*b*c^2*d^6-9/e^5/(e*x+d)^2*A*a*c^2*d^2-9/e^5/(e*x+d)^2*
A*b^2*c*d^2+15/e^6/(e*x+d)^2*A*b*c^2*d^3+9/2/e^4/(e*x+d)^2*B*a^2*c*d+9/2/e^4/(e*
x+d)^2*B*a*b^2*d-30/e^6/(e*x+d)*B*b^2*c*d^2+60/e^7/(e*x+d)*B*b*c^2*d^3+3/4/e^2/(
e*x+d)^4*A*d*a^2*b-3/4/e^3/(e*x+d)^4*A*d^2*a^2*c-3/4/e^3/(e*x+d)^4*A*d^2*a*b^2-3
/4/e^5/(e*x+d)^4*A*d^4*a*c^2-3/4/e^5/(e*x+d)^4*A*d^4*b^2*c+3/4/e^6/(e*x+d)^4*A*b
*c^2*d^5+12/e^5/(e*x+d)*A*b^2*c*d-30/e^6/(e*x+d)*A*b*c^2*d^2-30/e^6/(e*x+d)*B*a*
c^2*d^2+12/e^5/(e*x+d)*A*a*c^2*d-15/e^6*ln(e*x+d)*A*b*c^2*d+6/e^5*ln(e*x+d)*B*a*
b*c-15/e^6*ln(e*x+d)*B*a*c^2*d-15/e^6*ln(e*x+d)*B*b^2*c*d+3/4/e^4/(e*x+d)^4*B*d^
3*a*b^2+3/4/e^4/(e*x+d)^4*B*d^3*a^2*c-45/2/e^7/(e*x+d)^2*B*b*c^2*d^4-3/4/e^3/(e*
x+d)^4*B*d^2*a^2*b+15/e^6/(e*x+d)^2*B*a*c^2*d^3+15/e^6/(e*x+d)^2*B*b^2*c*d^3-1/4
/e/(e*x+d)^4*A*a^3+1/2*c^3/e^5*A*x^2-1/3/e^2/(e*x+d)^3*B*a^3+1/e^5*ln(e*x+d)*B*b
^3-1/e^4/(e*x+d)*A*b^3+1/4/e^4/(e*x+d)^4*A*d^3*b^3-1/4/e^7/(e*x+d)^4*A*c^3*d^6+1
/4/e^2/(e*x+d)^4*B*d*a^3-1/4/e^5/(e*x+d)^4*B*d^4*b^3+1/4/e^8/(e*x+d)^4*B*c^3*d^7
+3/2*c^2/e^5*B*x^2*b-5/2*c^3/e^6*B*x^2*d+3/2/e^4/(e*x+d)^2*A*b^3*d-15/2/e^7/(e*x
+d)^2*A*c^3*d^4-3/2/e^3/(e*x+d)^2*B*a^2*b-3/e^5/(e*x+d)^2*B*b^3*d^2+21/2/e^8/(e*
x+d)^2*B*c^3*d^5+3*c^2/e^5*A*b*x-5*c^3/e^6*A*d*x+3*c^2/e^5*B*a*x+3*c/e^5*B*b^2*x
+15*c^3/e^7*B*d^2*x-1/e^2/(e*x+d)^3*A*a^2*b-1/e^4/(e*x+d)^3*A*b^3*d^2+2/e^7/(e*x
+d)^3*A*c^3*d^5+4/3/e^5/(e*x+d)^3*B*b^3*d^3-7/3/e^8/(e*x+d)^3*B*c^3*d^6+3/e^5*ln
(e*x+d)*A*a*c^2+3/e^5*ln(e*x+d)*A*b^2*c+15/e^7*ln(e*x+d)*A*c^3*d^2-35/e^8*ln(e*x
+d)*B*c^3*d^3+20/e^7/(e*x+d)*A*c^3*d^3-3/e^4/(e*x+d)*B*a^2*c-3/e^4/(e*x+d)*B*a*b
^2+4/e^5/(e*x+d)*B*b^3*d-35/e^8/(e*x+d)*B*c^3*d^4-3/2/e^3/(e*x+d)^2*A*a^2*c-3/2/
e^3/(e*x+d)^2*A*a*b^2

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Maxima [A]  time = 0.729892, size = 1193, normalized size = 2.24 \[ \text{result too large to display} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate((c*x^2 + b*x + a)^3*(B*x + A)/(e*x + d)^5,x, algorithm="maxima")

[Out]

-1/12*(319*B*c^3*d^7 + 3*A*a^3*e^7 - 171*(3*B*b*c^2 + A*c^3)*d^6*e + 231*(B*b^2*
c + (B*a + A*b)*c^2)*d^5*e^2 - 25*(B*b^3 + 3*A*a*c^2 + 3*(2*B*a*b + A*b^2)*c)*d^
4*e^3 + 3*(3*B*a*b^2 + A*b^3 + 3*(B*a^2 + 2*A*a*b)*c)*d^3*e^4 + 3*(B*a^2*b + A*a
*b^2 + A*a^2*c)*d^2*e^5 + (B*a^3 + 3*A*a^2*b)*d*e^6 + 12*(35*B*c^3*d^4*e^3 - 20*
(3*B*b*c^2 + A*c^3)*d^3*e^4 + 30*(B*b^2*c + (B*a + A*b)*c^2)*d^2*e^5 - 4*(B*b^3
+ 3*A*a*c^2 + 3*(2*B*a*b + A*b^2)*c)*d*e^6 + (3*B*a*b^2 + A*b^3 + 3*(B*a^2 + 2*A
*a*b)*c)*e^7)*x^3 + 18*(63*B*c^3*d^5*e^2 - 35*(3*B*b*c^2 + A*c^3)*d^4*e^3 + 50*(
B*b^2*c + (B*a + A*b)*c^2)*d^3*e^4 - 6*(B*b^3 + 3*A*a*c^2 + 3*(2*B*a*b + A*b^2)*
c)*d^2*e^5 + (3*B*a*b^2 + A*b^3 + 3*(B*a^2 + 2*A*a*b)*c)*d*e^6 + (B*a^2*b + A*a*
b^2 + A*a^2*c)*e^7)*x^2 + 4*(259*B*c^3*d^6*e - 141*(3*B*b*c^2 + A*c^3)*d^5*e^2 +
195*(B*b^2*c + (B*a + A*b)*c^2)*d^4*e^3 - 22*(B*b^3 + 3*A*a*c^2 + 3*(2*B*a*b +
A*b^2)*c)*d^3*e^4 + 3*(3*B*a*b^2 + A*b^3 + 3*(B*a^2 + 2*A*a*b)*c)*d^2*e^5 + 3*(B
*a^2*b + A*a*b^2 + A*a^2*c)*d*e^6 + (B*a^3 + 3*A*a^2*b)*e^7)*x)/(e^12*x^4 + 4*d*
e^11*x^3 + 6*d^2*e^10*x^2 + 4*d^3*e^9*x + d^4*e^8) + 1/6*(2*B*c^3*e^2*x^3 - 3*(5
*B*c^3*d*e - (3*B*b*c^2 + A*c^3)*e^2)*x^2 + 6*(15*B*c^3*d^2 - 5*(3*B*b*c^2 + A*c
^3)*d*e + 3*(B*b^2*c + (B*a + A*b)*c^2)*e^2)*x)/e^7 - (35*B*c^3*d^3 - 15*(3*B*b*
c^2 + A*c^3)*d^2*e + 15*(B*b^2*c + (B*a + A*b)*c^2)*d*e^2 - (B*b^3 + 3*A*a*c^2 +
3*(2*B*a*b + A*b^2)*c)*e^3)*log(e*x + d)/e^8

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Fricas [A]  time = 0.266576, size = 1813, normalized size = 3.4 \[ \text{result too large to display} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate((c*x^2 + b*x + a)^3*(B*x + A)/(e*x + d)^5,x, algorithm="fricas")

[Out]

1/12*(4*B*c^3*e^7*x^7 - 319*B*c^3*d^7 - 3*A*a^3*e^7 + 171*(3*B*b*c^2 + A*c^3)*d^
6*e - 231*(B*b^2*c + (B*a + A*b)*c^2)*d^5*e^2 + 25*(B*b^3 + 3*A*a*c^2 + 3*(2*B*a
*b + A*b^2)*c)*d^4*e^3 - 3*(3*B*a*b^2 + A*b^3 + 3*(B*a^2 + 2*A*a*b)*c)*d^3*e^4 -
3*(B*a^2*b + A*a*b^2 + A*a^2*c)*d^2*e^5 - (B*a^3 + 3*A*a^2*b)*d*e^6 - 2*(7*B*c^
3*d*e^6 - 3*(3*B*b*c^2 + A*c^3)*e^7)*x^6 + 12*(7*B*c^3*d^2*e^5 - 3*(3*B*b*c^2 +
A*c^3)*d*e^6 + 3*(B*b^2*c + (B*a + A*b)*c^2)*e^7)*x^5 + 4*(139*B*c^3*d^3*e^4 - 5
1*(3*B*b*c^2 + A*c^3)*d^2*e^5 + 36*(B*b^2*c + (B*a + A*b)*c^2)*d*e^6)*x^4 + 4*(1
36*B*c^3*d^4*e^3 - 24*(3*B*b*c^2 + A*c^3)*d^3*e^4 - 36*(B*b^2*c + (B*a + A*b)*c^
2)*d^2*e^5 + 12*(B*b^3 + 3*A*a*c^2 + 3*(2*B*a*b + A*b^2)*c)*d*e^6 - 3*(3*B*a*b^2
+ A*b^3 + 3*(B*a^2 + 2*A*a*b)*c)*e^7)*x^3 - 6*(74*B*c^3*d^5*e^2 - 66*(3*B*b*c^2
+ A*c^3)*d^4*e^3 + 126*(B*b^2*c + (B*a + A*b)*c^2)*d^3*e^4 - 18*(B*b^3 + 3*A*a*
c^2 + 3*(2*B*a*b + A*b^2)*c)*d^2*e^5 + 3*(3*B*a*b^2 + A*b^3 + 3*(B*a^2 + 2*A*a*b
)*c)*d*e^6 + 3*(B*a^2*b + A*a*b^2 + A*a^2*c)*e^7)*x^2 - 4*(214*B*c^3*d^6*e - 126
*(3*B*b*c^2 + A*c^3)*d^5*e^2 + 186*(B*b^2*c + (B*a + A*b)*c^2)*d^4*e^3 - 22*(B*b
^3 + 3*A*a*c^2 + 3*(2*B*a*b + A*b^2)*c)*d^3*e^4 + 3*(3*B*a*b^2 + A*b^3 + 3*(B*a^
2 + 2*A*a*b)*c)*d^2*e^5 + 3*(B*a^2*b + A*a*b^2 + A*a^2*c)*d*e^6 + (B*a^3 + 3*A*a
^2*b)*e^7)*x - 12*(35*B*c^3*d^7 - 15*(3*B*b*c^2 + A*c^3)*d^6*e + 15*(B*b^2*c + (
B*a + A*b)*c^2)*d^5*e^2 - (B*b^3 + 3*A*a*c^2 + 3*(2*B*a*b + A*b^2)*c)*d^4*e^3 +
(35*B*c^3*d^3*e^4 - 15*(3*B*b*c^2 + A*c^3)*d^2*e^5 + 15*(B*b^2*c + (B*a + A*b)*c
^2)*d*e^6 - (B*b^3 + 3*A*a*c^2 + 3*(2*B*a*b + A*b^2)*c)*e^7)*x^4 + 4*(35*B*c^3*d
^4*e^3 - 15*(3*B*b*c^2 + A*c^3)*d^3*e^4 + 15*(B*b^2*c + (B*a + A*b)*c^2)*d^2*e^5
- (B*b^3 + 3*A*a*c^2 + 3*(2*B*a*b + A*b^2)*c)*d*e^6)*x^3 + 6*(35*B*c^3*d^5*e^2
- 15*(3*B*b*c^2 + A*c^3)*d^4*e^3 + 15*(B*b^2*c + (B*a + A*b)*c^2)*d^3*e^4 - (B*b
^3 + 3*A*a*c^2 + 3*(2*B*a*b + A*b^2)*c)*d^2*e^5)*x^2 + 4*(35*B*c^3*d^6*e - 15*(3
*B*b*c^2 + A*c^3)*d^5*e^2 + 15*(B*b^2*c + (B*a + A*b)*c^2)*d^4*e^3 - (B*b^3 + 3*
A*a*c^2 + 3*(2*B*a*b + A*b^2)*c)*d^3*e^4)*x)*log(e*x + d))/(e^12*x^4 + 4*d*e^11*
x^3 + 6*d^2*e^10*x^2 + 4*d^3*e^9*x + d^4*e^8)

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate((B*x+A)*(c*x**2+b*x+a)**3/(e*x+d)**5,x)

[Out]

Timed out

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GIAC/XCAS [A]  time = 0.262394, size = 1, normalized size = 0. \[ \mathit{Done} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate((c*x^2 + b*x + a)^3*(B*x + A)/(e*x + d)^5,x, algorithm="giac")

[Out]

Done